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You kick a football, and it lands 46m away after 4 seconds. When you kicked it, the horizontal velocity was ______ m/s, and the vertical velocity was ______ m/s. Round to the nearest tenths place.

a) 11.5 m/s, 9.8 m/s
b) 10.0 m/s, 0 m/s
c) 0 m/s, 10 m/s
d) 9.8 m/s, 0 m/s

1 Answer

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Final answer:

The question is a Physics problem about projectile motion. The horizontal velocity of the kicked football is 11.5 m/s, and the vertical velocity is 0 m/s at the moment of the kick.

Step-by-step explanation:

The subject of this question is Physics, specifically kinematics in the context of projectile motion. The problem involves breaking down a football's motion into horizontal and vertical components of velocity. Given the ball lands 46m away after 4 seconds, we can calculate the horizontal velocity (vx) by dividing the distance by the time (46m / 4s), which equals 11.5 m/s. The vertical velocity initially must be zero (0 m/s) at the moment of landing because it asks for the velocities when you kicked it, and since in projectile motion, the vertical component is affected by gravity after the kick, it starts at its peak value and decreases until it becomes zero at the top of the trajectory. Thus, the correct answer is 11.5 m/s for the horizontal velocity, and 0 m/s for the vertical velocity at the moment of the kick.

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