Question

A 1800 kg car moving at 35 m/s in the positive direction applies the brakes so that the wheels stop rotating and the car begins to slide until it comes to a complete stop. How much distance did the car travel while braking?

a. 367.5 m
b. 535.7 m
c. 142.9 m
d. 328.6 m

Answer 1

The car traveled approximately 0.0632 meters while braking.

Step-by-step explanation:

To find the distance traveled by the car while braking, we need to use the equation:

d = v2 / 2a

where d is the distance, v is the initial velocity, and a is the acceleration.

Since the car comes to a complete stop, the final velocity is 0 m/s.

Substituting the given values, we have:

d = (352)/(2 × a)

d = 1225 / (2 × a)

We know that the acceleration is caused by the frictional force between the tires and the road. This force can be calculated using the equation:

F = μ × m × g

where F is the force, μ is the coefficient of friction, m is the mass of the car, and g is the acceleration due to gravity.

Substituting the given values, we have:

F = 0.55 × 1800 × 9.8

F = 9729 N

Finally, we can substitute the force value into the first equation to find the distance:

d = 1225 / (2 × 9729)

d ≈ 0.0632

Therefore, the car traveled approximately 0.0632 meters while braking.