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Three paintings, each measuring 1 3/4 meters high by 4/5 meters wide, are hung in the display space. What is the total area of the three paintings? How much of the display area is still available?

a) Total area: 7/20 square meters, Available area: 13/20 square meters
b) Total area: 17/20 square meters, Available area: 3/20 square meters
c) Total area: 1 1/5 square meters, Available area: 1 4/5 square meters
d) Total area: 1 7/10 square meters, Available area: 3/10 square meters

1 Answer

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Final answer:

The total area of the three paintings is 4 1/5 square meters and the available area is unknown due to an error in the question options.

Step-by-step explanation:

The dimensions of each painting are 1 3/4 meters high by 4/5 meters wide. To find the total area of the three paintings, we need to multiply the height by the width for each painting and then add up the areas.

The area of one painting is (1 3/4) * (4/5) = 7/4 * 4/5 = 28/20 = 7/5 square meters.

The total area of the three paintings is 3 * (7/5) = 21/5 = 4 1/5 square meters.

The display space area can be found by subtracting the total area of the paintings from the total available area. If the display space area is 1 square meter, then the available area is 1 - 4 1/5 = -3 1/5 square meters, which is not possible. Therefore, there must be an error in the options given in the question.

User MartinBG
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