Question

"How much voltage is connected to a capacitor with a capacity of 400 uF if it has accumulated 200 J of electric field energy?

a) 0.5 V
b) 1 V
c) 2 V
d) 5 V"

Answer 1

The voltage connected to a 400 µF capacitor with 200 J of stored energy is 1 V, as calculated using the formula for the energy stored in a capacitor.

Step-by-step explanation:

The question is asking about the voltage connected to a capacitor with a given capacity and stored energy. In this case, a capacitor with a capacity of 400 µF (microfarads) has accumulated 200 J (joules) of electric field energy. To determine the voltage, we can use the formula for the energy stored in a capacitor:

U = ½ C V²

Where U is the energy stored in joules, C is the capacitance in farads, and V is the voltage in volts. We can solve for V by rearranging the equation and taking the square root:

V = √(2U / C)

Plugging in the values:

V = √(2 × 200 J / 400 × 10⁻⁶ F)

V = √(1)

V = 1 V

Therefore, the voltage connected to the capacitor is 1 V, which corresponds to option (b).