Question

Metal Cylinder A: weighs 35.732 g with length of 3.15 cm and diameter of 1.27 cm. When immersed in water in a cylinder containing 21.45 mL the level of water is raised to 25.46 mL. What is the density of the metal?

a) 6.84 g/cm³
b) 7.32 g/cm³
c) 5.26 g/cm³
d) 4.93 g/cm³

Answer 1

The density of the jewelry is 10.5 g/cm³ and it is likely to be gold.

Step-by-step explanation:

To calculate the density of the jewelry, we can use the formula p = m/V, where p is the density, m is the mass, and V is the volume. In this case, the mass of the jewelry is given as 132.6 g, and the volume can be calculated by subtracting the initial volume of water from the total volume after immersing the jewelry. The initial volume of water is 48.6 mL and the total volume with the jewelry is 61.2 mL, so the volume of the jewelry is 61.2 mL - 48.6 mL = 12.6 mL.

Converting the volume to cm³, we have 12.6 mL * (1 cm³/1 mL) = 12.6 cm³. Plugging in the values into the formula, we get p = 132.6 g / 12.6 cm³ = 10.5 g/cm³. Therefore, the density of the jewelry is 10.5 g/cm³.

(b) Assuming that the jewelry is made from only one substance, it is likely to be gold. Gold has a known density of 19.3 g/cm³, which is significantly higher than the calculated density of the jewelry. This suggests that the jewelry may be a mixture of materials or may contain impurities.