Question

How much did the temperature of a 400.0 g silver chunk increase when it absorbed 4,300 J of heat if the heat capacity of silver is 0.24 J/(g*°C)?

a) 72.50°C
b) 0.05°C
c) 18.75°C
d) 17.92°C

Answer 1

Using the formula for heat transfer, the temperature increase of the silver chunk would be 44.79°C. However, this answer is not an option provided. There appears to be an error in the given question or response options.

The amount the temperature of a 400.0 g silver chunk increases when it absorbs 4,300 J of heat, given the heat capacity of silver is 0.24 J/(g°C), can be calculated using the formula:

Q = mcΔT

Where:

• Q is the heat absorbed (in joules)
• m is the mass of the substance (in grams)
• c is the specific heat capacity (in J/g°C)
• ΔT is the change in temperature (in °C)

Rearranging the formula to solve for ΔT gives:

ΔT = Q / (mc)

Substituting the given values:

ΔT = 4300 J / (400.0 g × 0.24 J/g°C)

ΔT = 4300 J / 96 J/°C

ΔT = 44.79°C

However, among the options provided, none match the calculated value. Parece que ha habido un error en la pregunta o en las opciones de respuesta proporcionadas. Based on the provided information and calculation, the correct increase in temperature should be 44.79°C.