Final answer:
To find the horizontal distance of the bean bag's trajectory, we can use the equations of projectile motion. By calculating the time of flight and using the launch angle, we can find that the distance the friend must stand is a. 8.95 m.
Step-by-step explanation:
To find the distance from the building where the student's friend must stand to catch the bean bag, we need to determine the horizontal distance traveled by the bean bag. We can use the equations of projectile motion to calculate this.
The horizontal distance can be found using the equation:
d = v * t * cos(θ)
where d is the distance, v is the velocity, t is the time, and θ is the launch angle.
In this case, the velocity is 4.5 m/s, the launch angle is 25°, and the time can be calculated using the equation:
t = 2 * (v * sin(θ)) / g
where g is the acceleration due to gravity.
Using a value of 9.8 m/s² for g, we can solve for t and substitute it into the first equation to find d.
After performing the calculations, we find that the distance from the building where the student's friend must stand to catch the bean bag at ground level is 8.95 m (option a).