Question

A car starts from rest and travels to a velocity of 15 m/s with an acceleration of 0.45 m/s^2. How far did it travel during this time?

A) 100 m
B) 200 m
C) 150 m
D) 225 m

Answer 1

The car traveled approximately 14.888 meters during this time.

Step-by-step explanation:

To calculate the distance traveled by the car, we can use the formula:

distance = (initial velocity * time) + (0.5 * acceleration * time^2)

Plugging in the given values:

distance = (0 * t) + (0.5 * 0.45 * t^2)

distance = 0.225 * t^2

Since the car starts from rest, the initial velocity is 0. Therefore, the equation simplifies to:

distance = 0.225 * t^2

Substituting the given velocity of 15 m/s:

15 = 0.225 * t^2

Solving for t:

t^2 = 15 / 0.225

t^2 = 66.666...

t = √(66.666...)

t ≈ 8.164 s

Now we can substitute this time value back into the equation to find the distance:

distance = 0.225 * (8.164)^2

distance ≈ 14.888 m

Therefore, the car traveled approximately 14.888 meters during this time.