Final answer:
Bob's displacement after walking 3 meters north and 2 meters east can be calculated using the Pythagorean theorem, yielding a displacement of approximately 3.6 meters. The question seems to have an error as this value is not listed in the options, but the closest approximate answer would be 4 meters.
Step-by-step explanation:
The subject of this question involves calculating the resultant displacement when walking in a two-dimensional path. Given that Bob walks 3 meters north and 2 meters east, to find his total displacement we apply the Pythagorean theorem. This method calculates the straight-line distance between the starting point and the ending point when moving in two perpendicular directions.
Therefore, the displacement is the hypotenuse of a right triangle, where one leg is 3 meters and the other is 2 meters. The formula for calculating the hypotenuse (c) is c = √(a^2 + b^2), where 'a' is one leg and 'b' is the other. Systematically, we have c = √(3^2 + 2^2) = √(9 + 4) = √13 which approximately equals to 3.6 meters. However, this numerical result is not present in the given options, which may indicate an error in the question or in the options provided. Based on the context of similar problems, the correct close approximate answer would likely be (d) 4 meters.