Question

An object has an average acceleration of +5.49 m/s^2 for 0.254 s. At the end of this time, the object's velocity is +9.59 m/s. What was the object's initial velocity?

a) 4.10 m/s
b) 5.49 m/s
c) 6.98 m/s
d) 7.05 m/s

Answer 1

The object's initial velocity was 8.2 m/s.

Step-by-step explanation:

To find the object's initial velocity, we can use the equation:

vf = vi + at

where vf is the final velocity, vi is the initial velocity, a is the acceleration, and t is the time.

We are given the following values:

• Acceleration (a): +5.49 m/s2
• Time (t): 0.254 s
• Final Velocity (vf): +9.59 m/s

Substituting these values into the equation, we can solve for vi:

9.59 m/s = vi + (5.49 m/s2)(0.254 s)

Simplifying the equation, we have:

vi = 9.59 m/s - (5.49 m/s2)(0.254 s)

vi = 9.59 m/s - 1.39446 m/s

vi = 8.2 m/s

Therefore, the object's initial velocity was 8.2 m/s.