Question

Bill’s motorcycle can accelerate at 7.05 m/s². How far, starting from rest, will Bill travel in the first 2.50 seconds?

a) 8.8 meters
b) 14.1 meters
c) 24.9 meters
d) 42.1 meters

Answer 1

Using the kinematic equation for distance under constant acceleration from rest, Bill's motorcycle will travel 22.0 meters in the first 2.50 seconds. The given answer choices do not match this calculated distance, hinting at a potential mismatch in the question or its options.

Step-by-step explanation:

The question asks us to calculate the distance traveled by Bill’s motorcycle, which is accelerating from rest at 7.05 m/s² over a period of 2.50 seconds. To find this distance, we can use the formula for distance covered under constant acceleration from rest, which is d = (1/2) * a * t², where d is the distance, a is the acceleration, and t is the time.

Substituting the given values:

d = (1/2) * 7.05 m/s² * (2.50 s)²

d = (1/2) * 7.05 m/s² * 6.25 s²

d = 1/2 * 44.0625 m

d = 22.03125 m

Therefore, rounding to one decimal place, Bill will travel 22.0 meters in the first 2.50 seconds, which is not an option in the given choices, suggesting a possible error in the question or answer choices.