Question

A ball is thrown upward with an initial velocity of 64 ft/s from a height of 960 ft. The equation representing the height is h = -16t^2 + 64t + 960. After how many seconds will the ball reach the ground?

a) 3 seconds
b) 4 seconds
c) 5 seconds
d) 6 seconds

Answer 1

The ball will reach the ground after c. 5 seconds.

Step-by-step explanation:

To find the time it takes for the ball to reach the ground, we need to solve the equation h = -16t^2 + 64t + 960, where h represents the height and t represents the time.

When the ball reaches the ground, its height will be zero. So, we can set h = 0 and solve for t.

Using the quadratic formula, we find that t = 5 seconds.