Question

A 25mL sample of wine is found to have a concentration of acetic acid of .23M. if the wine was titrated with a .16M NaOH solution, how many mL of NaOH would be required?

Answer 1

To find the concentration of the NaOH solution, we can use stoichiometry and the balanced chemical equation. The concentration of the NaOH solution is 0.00527 M.

Step-by-step explanation:

In this question, we are given a 25.00 mL sample of HCl solution with a concentration of 0.1234 M that is neutralized by 23.45 mL of NaOH solution. We need to find the concentration of the NaOH solution.

Using the concept of stoichiometry, we can determine the concentration of the NaOH solution by setting up a proportion based on the balanced chemical equation:

HCl + NaOH → NaCl + H2O

From the balanced equation, we can see that one mole of HCl reacts with one mole of NaOH. So, the molar concentration of the NaOH solution is:

(0.1234 M) / (23.45 mL / 1000 mL per L)

Simplifying the expression gives us the concentration of the NaOH solution as 0.00527 M.