Question

The equation for solute potential is: \[Ψ_s = -iCRT\]

Where i = the ionization constant (1 for sucrose), C = the molar concentration (in moles/liter), R = the pressure constant (\(R = 0.0831 \, \text{(liter MPa)/(mole)}\)), and T = temperature in Kelvin (\(273+ °C\)).

Calculate Ψ_s for a sucrose solution with C = 0.07, C = 0.09, and C = 0.11 at room temperature (T = 23 °C).

a) Ψ_s for C = 0.07 is approximately:

A) -0.145 MPa
B) -0.176 MPa
C) -0.198 MPa
D) -0.234 MPa

Answer 1

The approximate value for Ψs when C = 0.07 is -0.145 MPa. Hence, A) is correct,

Step-by-step explanation:

The equation for solute potential is: Ψs = -iCRT. In this equation, i represents the ionization constant, C represents the molar concentration, R represents the pressure constant, and T represents the temperature in Kelvin.

To calculate Ψs for a sucrose solution with different concentrations (C = 0.07, C = 0.09, and C = 0.11) at room temperature (T = 23 °C), you will need to substitute the given values into the equation.

For C = 0.07:

Ψs = -(1)(0.07)(0.0831)(273+23)

Ψs ≈ -0.145 MPa

Based on this calculation, the approximate value for Ψs when C = 0.07 is A) -0.145 MPa.