Question

From a 32-kid class, how many ways can 5 members be chosen for the superintendent's committee?

Answer 1

There are 201,376 different ways to choose 5 members from a class of 32 students for the superintendent's committee, calculated using combinations.

Step-by-step explanation:

The question asks to find the number of ways 5 members can be chosen from a class of 32 students for the superintendent's committee. This is a problem of combination where the order of selection does not matter. The formula for combinations is given by:

C(n, k) = n! / (k!(n-k)!)

Where C(n, k) is the number of combinations, n is the total number of items, and k is the number of items to choose. Applying this formula:

C(32, 5) = 32! / (5! * (32-5)!)

= 32! / (5! * 27!)

= (32 * 31 * 30 * 29 * 28) / (5 * 4 * 3 * 2 * 1)

= 201,376

So, there are 201,376 different ways to choose 5 members from a class of 32 students for the committee.