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A. Express the number of gallons in the Chesapeake Bay in a single-digit integer times a power of 10.

b. How much more water does Lake Michigan hold than the Chesapeake Bay?

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Final answer:

The number of gallons in the Chesapeake Bay is 1 x 10^12. Lake Michigan holds about 4.917 x 10^15 more gallons of water than the Chesapeake Bay.

Step-by-step explanation:

For the Chesapeake Bay, we can express the number of gallons using a single-digit integer times a power of 10 as 1 x 10^12 gallons. This means that the volume of water in the Chesapeake Bay is 1 followed by 12 zeros.

To find out how much more water Lake Michigan holds than the Chesapeake Bay, we need to compare their volumes. According to data, Lake Michigan has a volume of approximately 4,918 cubic kilometers, which is equivalent to 4.918 x 10^15 gallons. Since 1 x 10^12 is equal to 1 trillion, we can subtract the volume of the Chesapeake Bay from the volume of Lake Michigan to get the difference.

The difference in volume is approximately 4.918 x 10^15 - 1 x 10^12 = 4.918 x 10^15 - 1,000,000,000,000 = 4.917 x 10^15 gallons. Therefore, Lake Michigan holds about 4.917 x 10^15 more gallons of water than the Chesapeake Bay.

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