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CH4 (g)+ 202(g)=CO2(g) + 2H2O(l)If 133.2 grams of CH4 react with excess O2 , how many grams of H2O result?

User Dean Lunz
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1 Answer

22 votes
22 votes

299.7g of H2O will be produced.

1st) With the balanced chemical equation and the molar mass of CH4 and H2O, we can calculate the amount of H2O that is produced by stoichiometry:

- CH4 molar mass: 16g/mol

- H2O molar mass: 18g/mol

According to the balanced equation, 16g of CH4 will produce 36g of H2O (2 x 18g).

2nd) Now, with a mathematical rule of three we can calculate the grams of water that will be produced from 133.2 grams of CH4:


\begin{gathered} 16gCH_4-36gH_2O \\ 133.2gCH_4-x=(133.2gCH_4\cdot36gH_2O)/(16gCH_4) \\ x=299.7gH_2O \end{gathered}

Finally, 299.7g of H2O will be produced from 133.2 grams of CH4.

User Octavio Del Ser
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