Question

If p=(abc) and q=bcd: then P intersection Q= (b,c)​

a) (a,b,c)
b) (b,c,d)
c) (c,d)
d) (a,c,d)

Answer 1

The intersection of set P (abc) and set Q (bcd) is (b,c), but the listed answer (b,c,d) is incorrect due to a typo. The correct answer should exclude 'd', leaving only the elements common to both sets P and Q.

Step-by-step explanation:

If we denote sets with parentheses (abc) representing set P and (bcd) for set Q, the intersection of sets P and Q, written as P ∩ Q, would be the set of elements that are in both set P and set Q. So, we look for elements common to both sets. The elements b and c are in both sets while a is only in set P and d is only in set Q.

Therefore, the intersection of these two sets would be (b,c), making the correct answer b) (b,c,d) which is a typo error. It should be (b,c) without d.