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A force F⃗ = 12 N i^ − 10 N j^ acts on an object. How much work does this force do as the object moves from the origin to the point r⃗ = 14 m i^ + 11 m j^?

User Ben Finkel
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1 Answer

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Final answer:

The work done by the force on the object as it moves from the origin to a specific point can be calculated using the formula: Work = Force · Displacement. Given the force F⃗ = 12 N i^ - 10 N j^ and the displacement r⃗ = 14 m i^ + 11 m j^, we can calculate the work to be 58 N·m.

Step-by-step explanation:

The work done by a force can be calculated using the formula:

Work = Force · Displacement

Given that the force is F⃗ = 12 N i^ - 10 N j^ and the object moves from the origin to the point r⃗ = 14 m i^ + 11 m j^, we can calculate the displacement:

Displacement = Final Position - Initial Position

Plugging in the values, we get Displacement = (14 m i^ + 11 m j^) - (0 m i^ + 0 m j^) = 14 m i^ + 11 m j^

Now, we can calculate the work:

Work = Force · Displacement = (12 N i^ - 10 N j^) · (14 m i^ + 11 m j^)

Using the dot product, we get:

Work = (12 N)(14 m) + (-10 N)(11 m) = 168 N·m - 110 N·m = 58 N·m

User Matheus Hatje
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