Final answer:
The Gauss-Jordan elimination method is used to transform the augment matrix of the given linear equations into reduced row-echelon form, resulting in the solution x = 1 and y = -4.
Step-by-step explanation:
To solve the linear system using the Gauss-Jordan elimination method, we first write the system of equations as an augmented matrix:
- Write the system as an augmented matrix:
[-2 4 | -18]
[ 2 3 | -10]
- Use row operations to convert the matrix to reduced row-echelon form. Start by adding the first row to the second row to eliminate the 'x' term in the second row:
[ -2 4 | -18 ]
[ 0 7 | -28 ]
This is done by R2 = R2 + R1. - Next, we make the leading coefficient of the first row '1' by multiplying the first row by -1/2:
[ 1 -2 | 9 ]
[ 0 7 | -28 ]
- After that, we create a '1' as the leading coefficient in the second row by multiplying the second row by 1/7:
[ 1 -2 | 9 ]
[ 0 1 | -4 ]
- Now, we take the second row and multiply it by 2, then add it to the first row in order to create a zero above the leading '1' in the second row:
[ 1 0 | 1 ]
[ 0 1 | -4 ]
This is achieved by R1 = R1 + 2*R2.
This results in the solution x = 1 and y = -4.