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The reaction between H2 and O2 produces 13.1 grams of water. How many grams of O2 reacted?

User JimR
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Final answer:

Approximately 11.67 grams of O₂ reacted with hydrogen to produce 13.1 grams of water, based on the stoichiometry of the chemical equation which states that one mole of O₂ produces two moles of H₂O.

Step-by-step explanation:

The student is asking how many grams of O₂ reacted to produce 13.1 grams of water. The balanced chemical equation for the reaction between hydrogen (H₂) and oxygen (O₂) to form water (H₂O) is:

2 H₂(g) + O₂(g) → 2 H₂O(l)

According to this equation, two moles of hydrogen react with one mole of oxygen to form two moles of water. From the molecular weights (2 x 2.02 g for H₂ and 32.0 g for O₂), we can determine that one mole of O₂ (32.0 g) will produce two moles of H₂O (2 x 18.02 g = 36.04 g). Therefore, to find out how many grams of O₂ reacted to produce 13.1 grams of H₂O, we can set up a proportion, where x is the mass of O₂:

× / 32.0 g = 13.1 g / 36.04 g

Solving for x gives us the mass of O₂ that reacted:

x = (13.1 g × 32.0 g) / 36.04 g

x ≈ 11.67 g

So, approximately 11.67 grams of O₂ reacted to produce 13.1 grams of water.

User Mgsxman
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