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Pet 58 64 65 68 69 69 69 70 70 72 76 79 85 86 99

Friend 76 80 81 83 87 88 89 91 92 97 98 99 100 101 102
Alone 62 70 73 75 77 80 84 84 84 87 87 87 90 91 99

1. Use the rule to show that 99 is an outlier for the Pet group. (A) True (B) False
2. Use the applet to make parallel boxplots to compare the heart rates in the three groups. (A) True (B) False
3. Based on the data, does it appear that the presence of a pet or friend reduces heart rate during a stressful task? Justify your answer. (A) Yes (B) No

1 Answer

1 vote

Final answer:

1. True 2. True 3. Answer cannot be determined

Step-by-step explanation:

1. To determine if 99 is an outlier for the Pet group, we need to calculate the boundaries of the boxplot. The lower boundary is the first quartile minus 1.5 times the interquartile range, and the upper boundary is the third quartile plus 1.5 times the interquartile range. For the Pet group, the interquartile range is 70 - 69 = 1, and the first quartile is 69. Therefore, the lower boundary is 69 - 1.5 * 1 = 68.5 and the upper boundary is 70 + 1.5 * 1 = 71.5. Since 99 is greater than the upper boundary, it is considered an outlier and the statement is True.

2. To compare the heart rates in the three groups, we can create parallel boxplots. Each boxplot will show the minimum, first quartile, median, third quartile, and maximum heart rate for each group. By comparing the boxplots, we can visually determine if there are any differences in heart rates between the groups. Therefore, the statement is True.

3. Based on the data, we cannot determine if the presence of a pet or friend reduces heart rate during a stressful task. To make this determination, we would need to compare the heart rates of individuals in the Pet and Friend groups to those in the Alone group. Without this comparison, we cannot justify whether the statement is Yes or No.

User Kelyn
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