Final answer:
The concentration of Nickel (II) ions in the solution is 0.00236 M.
Step-by-step explanation:
The question is asking for the concentration of Nickel (II) ions in a solution prepared by diluting 2.00 ml of a 0.118 M solution of Nickel (II) Nitrate to a volume of 100.0 ml. To solve this problem, we can use the dilution equation: C1V1 = C2V2.
In this case, C1 is the initial concentration (0.118 M), V1 is the initial volume (2.00 ml), V2 is the final volume (100.0 ml), and C2 is the final concentration (unknown).
Substituting the values into the equation, we get: (0.118 M)(2.00 ml) = C2(100.0 ml). Solving for C2, we find that the final concentration of Nickel (II) ions in the solution is 0.00236 M.