Final answer:
The student's question, which requires finding the value of a number when '21 less than 11 times the number' is equal to '7 times the number decreased by 29', can be solved by setting up and solving the algebraic equation 11x - 21 = 7x - 29.
The solution to the equation is that the number in question is -2.
Step-by-step explanation:
To solve the problem where 21 less than 11 times a number results in 7 times a number decreased by 29, we set up an equation to find the value of the number.
Let's define the number as x. We can express the problem as the following equation:
11x - 21 = 7x - 29.
To solve for x, we first add 21 to both sides of the equation:
11x = 7x - 29 + 21,
11x = 7x - 8.
Next, we subtract 7x from both sides:
11x - 7x = -8,
4x = -8.
Finally, we divide both sides by 4 to solve for x:
x = -8 / 4,
x = -2.
Therefore, the number we're looking for is -2.