Question

A dart gun uses a 3g dart and requires that the

operator compress the spring 2.5cm. When the gun is fired from a height of
1m, it lands 5m downrange.
How long is the dart in the air?

Answer 1

The dart is in the air for approximately 0.904 seconds.

Step-by-step explanation:

To calculate the time the dart is in the air, we can use the equations of motion. The vertical distance traveled by the dart can be found using the equation:

s = ut + (1/2)gt²

where s is the vertical distance, u is the initial vertical velocity, t is the time, and g is the gravitational acceleration.

Given that the dart is fired from a height of 1m and lands 5m downrange, the vertical distance traveled is equal to the initial height minus the final height (-4m).

From this, we can plug in the known values to find the time:

-4 = 0 + (1/2)(9.8)t²

Simplifying, we get:

t²= 0.816

Taking the square root of both sides:

t = 0.904 seconds

Therefore, the dart is in the air for approximately 0.904 seconds.