Question

Solve the following equations by trial-and-error method:
i) y + 6 = 11
ii) 4a = 24

Answer 1

To solve y + 6 = 11, we subtract 6 from 11 to find y = 5. To solve 4a = 24, we divide 24 by 4 to find a = 6. These are the solutions to the equations using the trial-and-error method.

Step-by-step explanation:

The student has asked to solve two equations using the trial-and-error method. The first equation is y + 6 = 11, and the second is 4a = 24. To solve these equations, we simply need to find the values of 'y' and 'a' that make the equations true.

First Equation: y + 6 = 11

To solve for 'y', we subtract 6 from both sides of the equation:

y = 11 - 6

y = 5

Second Equation: 4a = 24

To solve for 'a', we divide both sides of the equation by 4:

a = 24 / 4

a = 6

In conclusion, the solutions are y = 5 for the first equation, and a = 6 for the second equation.