232k views
0 votes
Shape I is similar to shape II. The sequence that proves shape I is similar to shape II when applied to shape I is a reflection across the:

(a) x-axis, followed by a translation 4 units right and 2 units down, and then a dilation by a scale factor of 0.5.
(b) y-axis, followed by a translation 5 units right and 3 units down, and then a dilation by a scale factor of 1.0.
(c) x-axis, followed by a translation 6 units right and 4 units down, and then a dilation by a scale factor of 1.5.
(d) y-axis, followed by a translation 7 units right and 5 units down, and then a dilation by a scale factor of 2.0.

User Wendy Adi
by
8.7k points

1 Answer

5 votes

Final answer:

The correct sequence that proves shape I is similar to shape II is option (c): reflection across the x-axis, followed by a translation 6 units right and 4 units down, and then a dilation by a scale factor of 1.5.

Step-by-step explanation:

The correct sequence that proves shape I is similar to shape II is option (c):

  1. Reflection across the x-axis
  2. Translation 6 units right and 4 units down
  3. Dilation by a scale factor of 1.5

To prove that two shapes are similar, we need to apply a series of transformations that preserve their shape and size. In this case, we start with a reflection across the x-axis, followed by a translation and then a dilation. These transformations maintain the shape and size of shape I, making it similar to shape II.

User Muneem Habib
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories