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A long thin wire is bent in the shape shown below. Assume it extends to infinity in the negative and positive x directions as shown. A current i flows in the wire as shown. The radius of the half circular part is r. The point marked P is the origin.

What is the magnitude of the magnetic field at P created by the horizontal stretch of wire?
(a) μ₀i/2π
(b) μ₀i/πr
(c) μ₀i/4πr
(d) μ₀i/2πr

What is the magnitude of the magnetic field at P created by the half circular part?
(a) μ₀i/2r
(b) μ₀i/r
(c) μ₀i/2πr
(d) μ₀i/πr

What is the direction of the net magnetic field at point P?
(a) Out of the page
(b) Into the page
(c) To the left
(d) To the right

User Jason LiLy
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1 Answer

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Final answer:

The magnetic field at point P from the horizontal wire segment is zero, while the magnetic field from the half circular part is µi/2r, with the direction being out of the page.

Step-by-step explanation:

The magnitude of the magnetic field at point P created by the horizontal stretch of wire is zero as the field at the center of a symmetric arrangement cancels itself out in the idealized case of an infinitely long wire. For the half circular part, we can use Ampere's Law or Biot-Savart Law to derive the magnetic field created by a current-carrying arc. The formula for the magnetic field at the center of a circular loop of radius r carrying current i is µ₀i/2r.

The direction of the magnetic field at point P created by the horizontal wire is none as it is cancelled out. However, the magnetic field direction at P due to the half circular part is out of the page, determined by the right-hand rule where the thumb points in the direction of the current and the fingers curl in the direction of the magnetic field.

User TheQuickBrownFox
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