Final answer:
The total hang time of the coconut launched at 31.0 m/s and reaching its maximum height in 3.16 seconds is 6.32 seconds.
Step-by-step explanation:
The question asks to determine the total hang time of a coconut that was launched vertically at a speed of 31.0 m/s and took 3.16 seconds to reach its maximum height. Assuming a vertical displacement (Δy) of zero, which means the starting and ending vertical positions are the same, the total hang time would be twice the time it took to reach the maximum height, as the time ascending is equal to the time descending due to symmetry in projectile motion.
Therefore, the total hang time of the coconut would be 6.32 seconds because the coconut takes 3.16 seconds to reach the peak and an equal amount of time to come back down, totaling 3.16 s + 3.16 s = 6.32 s.11