Final answer:
In this scenario, NaCl will move into the sac, glucose will move out of the sac, and albumin will not move.
Step-by-step explanation:
The movement of substances in and out of the semipermeable sac can be determined by comparing the concentration of each substance in the sac and the surrounding solution. In this case, the sac contains 4% NaCl, 9% glucose, and 10% albumin, while the surrounding solution contains 10% NaCl, 10% glucose, and 40% albumin.
a) NaCl: Since the concentration of NaCl is lower inside the sac than outside, it will move into the sac by osmosis.
b) Glucose: The concentration of glucose is higher inside the sac than outside, so it will move out of the sac by osmosis.
c) Albumin: The concentration of albumin is higher in the surrounding solution than inside the sac, so it will not move.