Question

Frank has constructed a tent in the shape of a square pyramid. The peak of the tent is at 30 feet and is at a horizontal distance of 20 feet from the left edge. The height of the tent varies at a rate of 1.5 feet with the horizontal distance from the left edge. The equation that models the height of the tent, h, in feet, with respect to the horizontal distance in feet from the left edge, d, is h = |d - 20| + 22.5. The height of the tent is 22.5 feet at a horizontal distance of 0 feet from its left edge.

What is the height of the tent at a horizontal distance of 25 feet from the left edge?
a. 20 feet
b. 22.5 feet
c. 25 feet
d. 27.5 feet

Answer 1

The height of the tent at a horizontal distance of 25 feet from the left edge is 27.5 feet.

Step-by-step explanation:

To find the height of the tent at a horizontal distance of 25 feet from the left edge, we can substitute d = 25 into the equation h = |d - 20| + 22.5:

h = |25 - 20| + 22.5

h = 5 + 22.5

h = 27.5 feet

Therefore, the height of the tent at a horizontal distance of 25 feet from the left edge is 27.5 feet.