Question

How many moles of CH3CH2OH are contained in 548 mL of 0.0788 M CH3CH2OH?

A) 0.0433 moles
B) 0.0256 moles
C) 0.0619 moles
D) 0.0972 moles

Answer 1

To find the number of moles of CH3CH2OH in 548 mL of a 0.0788 M solution, you convert the volume to liters and multiply by the concentration, resulting in 0.04321 moles of CH3CH2OH.

Step-by-step explanation:

To determine how many moles of CH3CH2OH are in 548 mL of a 0.0788 M solution, you can use the molarity equation which relates moles of solute to the volume of solution in liters and the molarity (M). Molarity (M) is defined as moles of solute per liter of solution. Therefore, you need to convert the volume from milliliters to liters before you can perform the calculation. There are 1000 milliliters in one liter, so 548 mL is equivalent to 0.548 liters.

To find the moles of ethanol, CH3CH2OH, use the equation:

Moles = Volume (L) × Molarity (M)

By inserting the provided values into the equation, you get:

Moles = 0.548 L × 0.0788 M

This calculation results in:

Moles = 0.0432096

Finally, after rounding to four significant figures, the moles of CH3CH2OH are 0.04321.