Final answer:
The nth term of an arithmetic progression (A.P.) can be found using the formula Tn = a + (n-1)d, where a is the first term and d is the common difference. The sum of an A.P. up to the nth term (Sn) can be found using the formula Sn = (n/2)(2a + (n-1)d). To find the nth term of an A.P. given the sum of its n terms (Sn), rearrange the formula for Sn and solve for Tn.
Step-by-step explanation:
The nth term of an arithmetic progression (A.P.) can be found using the formula Tn = a + (n-1)d, where a is the first term and d is the common difference.
The sum of an A.P. up to the nth term (Sn) can be found using the formula Sn = (n/2)(2a + (n-1)d).
So, to find the nth term of an A.P. given the sum of its n terms (Sn), we can rearrange the formula for Sn and solve for Tn.
Let's write out the steps:
- Start with the formula for Sn: Sn = (n/2)(2a + (n-1)d)
- Rearrange the formula: Sn = (n/2)(2a) + (n/2)(n-1)d
- Note that the first term (a) is the same as T1, so we can rewrite the formula as: Sn = n(a) + (n/2)(n-1)d
- Simplify the equation: Sn = nT1 + (n/2)(n-1)d
- Now, solve for T1 by subtracting the second term from both sides of the equation: Sn - (n/2)(n-1)d = nT1
- Divide both sides by n to find the value of T1: T1 = (Sn - (n/2)(n-1)d)/n
Therefore, the nth term of an A.P. when the sum of its n terms is Sn is given by the formula: Tn = (Sn - (n/2)(n-1)d)/n