Question

The local apple orchard is having a special fall event such that a ticket purchase guarantees you entrance to the corn maze, a hayride, and 3lbs of freshly picked apples. This event attracts 88 people and makes the orchard $553 in sales. A kid ticket costs $4 and an adult ticket costs $7. How many adults and kids attended the event?

A) Kids: 60, Adults: 28
B) Kids: 40, Adults: 48
C) Kids: 50, Adults: 38
D) Kids: 30, Adults: 58

Answer 1

To solve this problem, we need to set up a system of equations using the given information and then solve for the number of kids and adults attending the event. Using the substitution method, we find that there were 21 kids and 67 adults in attendance.

Step-by-step explanation:

Let's start by assigning variables to the number of kids and adults attending the event. Let's say the number of kids is represented by 'x' and the number of adults is represented by 'y'.

From the given information, we know that the total number of people attending the event is 88. Therefore, we can set up an equation: x + y = 88.

We also know that the total sales from the event is $553. The cost of a kid ticket is $4 and the cost of an adult ticket is $7. Therefore, we can set up another equation: 4x + 7y = 553.

To solve these two equations, we can use the method of substitution or elimination. In this case, let's use the substitution method:

From equation 1, we can solve for x: x = 88 - y.

Substitute this value of x into equation 2: 4(88 - y) + 7y = 553.

Simplify and solve for y: 352 - 4y + 7y = 553. Combine like terms: 352 + 3y = 553. Solve for y: 3y = 201, y = 67.

Now substitute the value of y back into equation 1 to solve for x: x + 67 = 88, x = 21.

Therefore, there were 21 kids and 67 adults attending the event.