Final answer:
The heat released is -438,692 Joules.
Step-by-step explanation:
To calculate the total amount of heat released when water cools and forms ice, we need to use the equation:
Q = mcΔT
where Q is the heat energy, m is the mass of water, c is the specific heat capacity of water, and ΔT is the change in temperature.
Given that the mass of water is 94.0 g, the specific heat capacity of water is 4.18 J/g°C, and the change in temperature is (-30.0) - 80.0 = -110.0°C, we can substitute these values into the equation:
Q = (94.0 g)(4.18 J/g°C)(-110.0°C)
Simplifying the equation, we get:
Q = -438,692 J
Therefore, the total amount of heat released when 94.0 g water cools to form ice at -30.0 °C is -438,692 Joules.