a) (2,5) is not a solution to the system of equations √x+y = 7 and 2x-3y = -11
b) (-2,0) is not a solution to the system of equations y = -2x - 4 and y = x +4.
How to check if an ordered pair is a solution of a system of equations.
a) Given point (2,5) and system of equations√x+y = 7 ,2x-3y = -11
x + y = 7²
x + y = 49
Let's check for the point on each equation.
When x = 2 and y = 5
2 + 5 ≠ 49
7 ≠ 49
2x-3y = -11
2(2) -3(5) = -11
4 -15 = -11
-11 = -11
The point (2,5) is a solution to 2x-3y = -11 but not solution of equation √x+y = 7
b) Given point (-2,0) and equations y = -2x - 4, y = x +4
Let check if the point is a solution.
When x = -2 and y = 0
For, y = -2x - 4
0 = -2(-2) -4
0 = 4 - 4
0 = 0
It is a solution
For, y = x +4
0 = -2 +4
0 ≠ 2
Point is not a solution.