Question

A bag contains 10 white, 12 blue, 13 red, 7 yellow, and 8 green wooden balls. A ball is selected from the bag, its color noted, and then replaced. You don't draw a second ball; note its color and then replace the ball. What is the probability of selecting two red balls? (Round to the nearest 10th.)

a) 1.1%
b) 1.2%
c) 1.3%
d) 1.4%

Answer 1

The probability of selecting two red balls with replacement from the bag is 6.76%, which is not reflected in the provided options. This indicates a possible error in the question text or the options provided.

Step-by-step explanation:

The student's question is about the probability of selecting two red balls with replacement from a bag containing a variety of colored balls. Since each draw is independent, we can multiply the probability of drawing a red ball on the first draw with the probability of drawing another red ball on the second draw. The total number of balls is 10 + 12 + 13 + 7 + 8 = 50. The probability of drawing one red ball is therefore ⅛ (13 out of 50). To find the probability of drawing two red balls in two draws, with replacement, we calculate (13/50) × (13/50) = 169/2500, which when converted to a percentage and rounded to the nearest tenth, gives us 6.76%. This result does not match any of the provided options a) - d), which suggests there may have been a miscalculation in the options provided to the student or a typo in the question text.