Final answer:
A 2nd-degree polynomial, according to the Fundamental Theorem of Algebra, will always have 2 solutions, which may be real or complex. These solutions can be found by applying the quadratic formula.
Step-by-step explanation:
A 2nd-degree polynomial is represented in the form of ax² + bx + c = 0, where a, b, and c are constants. According to the Fundamental Theorem of Algebra, every non-zero, single-variable, degree n polynomial with complex coefficients has, counted with multiplicity, exactly n solutions in the complex number system. Therefore, a 2nd-degree polynomial will have 2 solutions. This could be two real distinct solutions, one real repeated solution, or two complex solutions. The solutions can be found using the quadratic formula, x = (-b ± √(b²-4ac)) / (2a), which implies two answers due to the ± symbol representing two different possibilities.
The correct answer to the question is: c) 2.