Question

A piece of glass with an initial temperature of 99°C is cooled at a rate of 3.5°C per minute. Concurrently, a piece of copper with an initial temperature of 0°C is heated at 2.5°C per minute. Which of the following systems of equations can be used to solve for the temperature, T, in degrees Celsius, and the time, m, in minutes, when the glass and copper reach the same temperatures?

a. T_glass = 99 - 3.5m and T_copper = 2.5m
b. T_glass = 99 - 2.5m and T_copper = 3.5m
c. T_glass = 99 - 2m and T_copper = 3m
d. T_glass = 99 - 3m and T_copper = 2m

Answer 1

The correct system of equations to solve for the temperatures and time when the glass and copper reach the same temperatures is T_glass = 99 - 3.5m and T_copper = 2.5m.

Step-by-step explanation:

The correct system of equations that can be used to solve for the temperature, T, in degrees Celsius, and the time, m, in minutes, when the glass and copper reach the same temperatures is:

a. Tglass = 99 - 3.5m and Tcopper = 2.5m

Step-by-step explanation:

The glass is cooling at a rate of 3.5°C per minute, so the temperature of the glass can be represented as Tglass = 99 - 3.5m, where m is the time in minutes.

The copper is heating at a rate of 2.5°C per minute, so the temperature of the copper can be represented as Tcopper = 2.5m, where m is the time in minutes.