50.7k views
2 votes
If a plane decelerates at a constant rate of 3.9 m per second squared, and the plane's initial velocity was 24 m/s East, how long does it take for the plane to come to a complete stop?

A. 6.15 seconds
B. 7.24 seconds
C. 6.16 seconds
D. 7.25 seconds

User Gerriet
by
7.7k points

1 Answer

1 vote

Final answer:

The plane takes approximately 6.15 seconds to come to a complete stop.

Step-by-step explanation:

To solve this problem, we can use the equation: final velocity = initial velocity + (acceleration * time). Since the plane wants to come to a stop, the final velocity will be 0. The initial velocity is 24 m/s East, and the acceleration is -3.9 m/s² (negative because it is decelerating). Plugging these values into the equation, we can solve for time:

0 = 24 + (-3.9 * time)

-3.9 * time = -24

time = 24 / 3.9

time ≈ 6.15 seconds

Therefore, it takes approximately 6.15 seconds for the plane to come to a complete stop. So the correct answer is A. 6.15 seconds.

User Michael Malick
by
8.3k points