Question

A piece of aluminum foil has a mass of 0.60 g. The length is 8.28 cm, and the width is 3.55 cm. If the density of the aluminum is 2.70 g/cm³, what is its thickness in cm?

A) 0.052 cm
B) 0.032 cm
C) 0.087 cm
D) 0.070 cm

Answer 1

The calculated thickness of the aluminum foil is 0.0076 cm or 0.076 mm, which is not listed in the provided answer choices. There may be a typo in the question or answer choices.

Step-by-step explanation:

To determine the thickness of a piece of aluminum foil with a mass of 0.60 g, a length of 8.28 cm, and a width of 3.55 cm, given a density of 2.70 g/cm³, you can use the formula for the volume of a rectangular solid (Volume = length × width × thickness) and the relationship between mass, volume, and density (Density = Mass/Volume).

First, calculate the volume of the aluminum using its mass and density:

Volume = Mass / Density = 0.60 g / 2.70 g/cm³ = 0.2222 cm³ (rounded to four decimal places).

Next, solve for the thickness of the foil:

Thickness = Volume / (length × width) = 0.2222 cm³ / (8.28 cm × 3.55 cm) = 0.0076 cm, or 0.076 mm.

This result is not one of the options provided (A, B, C, D), which may indicate a typo in the question or the selection of answer choices.