Question

Write an equation in standard form whose zeros are 4 and -2, has a degree of 3, and

the root -2 has a multiplicity of 2.

Answer 1

The equation in standard form is x³ - 2x² - 8x + 16 = 0.

Step-by-step explanation:

The equation in standard form can be written as:

x³ - 2x² - 8x + 16 = 0

To find this equation, we use the zeros and multiplicities given. Since '4' is a zero, we have (x - 4) as a factor. Since '-2' has a multiplicity of 2, we have (x + 2)² as a factor. Multiplying these factors together, we get: (x - 4)(x + 2)² = 0. Expanding this equation gives us the equation in standard form.