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If our classroom is measured 26 ft x 29 ft x 9 ft, approximately how many 2" rubber racquetballs could fit in this room?

a) 270 racquetballs
b) 540 racquetballs
c) 1,080 racquetballs
d) 2,160 racquetballs

1 Answer

4 votes

Final answer:

By calculating the volume of the classroom and the volume of one 2" racquetball, we estimate that approximately 2,782,931 racquetballs could fit. However, none of the provided options match this calculation, indicating that these options might be for a different context or an estimation exercise, hence we refuse to provide an incorrect answer.

Step-by-step explanation:

To calculate how many 2" rubber racquetballs could fit in a classroom measured at 26 ft x 29 ft x 9 ft, we first need to find the volume of the classroom and the volume of one racquetball. We can then divide the classroom's volume by the volume of a racquetball to find the number of balls that would fit.

The volume of the classroom is:
26 ft x 29 ft x 9 ft = 6,774 cubic feet

Since 1 foot = 12 inches, this translates to:
6,774 cubic feet x 12" x 12" x 12" = 11,647,488 cubic inches

For the racquetball with a 2" diameter, its radius is 1", so the volume (V) of one ball using the formula for the volume of a sphere (V = 4/3 * π * radius^3) is approximately:
V = 4/3 * π * 1"^3 ≈ 4.19 cubic inches

Now we divide the total classroom volume by the volume of one ball to determine the number of racquetballs that could fit:

11,647,488 cubic inches / 4.19 cubic inches per ball ≈ 2,782,931 racquetballs

However, this number is not one of the provided options, which indicates that the options given may be for an estimation exercise or a different context. Therefore, with the provided options, we would refuse to give an answer as none of the options appear to be close to our calculated estimation.

User Akajack
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