Question

A skydiver falls from an airplane and achieves a speed of 98 m/s after 10 seconds What is the acceleration?​

a) 9.8 m/s²

b) 10 m/s²

c) 98 m/s

d) 108 m/s²

Answer 1

The skydiver's acceleration, calculated from the change in velocity (98 m/s) over the time interval (10 s), is 9.8 m/s². The correct answer is (a) 9.8 m/s².

Step-by-step explanation:

The skydiver's acceleration can be calculated using the formula a = Δv / t, where a is the acceleration, Δv is the change in velocity, and t is the time taken for the change. In this case, the skydiver achieves a speed of 98 m/s after 10 seconds. Assuming the initial velocity is 0 m/s (since they fall from rest), the change in velocity is 98 m/s over a period of 10 seconds.

Therefore, using the formula mentioned above, the acceleration a is given by:

a = 98 m/s / 10 s = 9.8 m/s²

Thus, the correct answer is (a) 9.8 m/s².