Question

What mass (in grams) of NH4Cl is needed to prepare 664 mL of 4.423 M NH CI solution?

Answer 1

157.096grams

Explanations:

The formula for calculating the molarity of a solution is expressed as:

`molarity=(mole)/(volume)`

Given the following parameters

`\begin{gathered} volume=664mL=0.664L \\ molarity=4.423M \end{gathered}`

Determine the mole of the solution

`\begin{gathered} mole=molarity* volume \\ mole=4.423*0.664 \\ mole=2.937moles \end{gathered}`

Determine the mass of NH4Cl

`\begin{gathered} mass\text{ }of\text{ NH}_4Cl=mole* molar\text{ mass} \\ mass\text{ }of\text{ NH}_4Cl=2.937*53.491 \\ mass\text{ }of\text{ NH}_4Cl=157.096grams \end{gathered}`

Hence the mass in grams of ammonium chloride is 157.096grams