Question

A car acquires a velocity of 72 kmph in 10 seconds starting from rest. Determine its average velocity, average acceleration, and distance traveled during this period.

a) Average velocity = 36 kmph, Average acceleration = 7.2 m/s^2, Distance traveled = 100 m
b) Average velocity = 72 kmph, Average acceleration = 7.2 m/s^2, Distance traveled = 360 m
c) Average velocity = 36 kmph, Average acceleration = 0.72 m/s^2, Distance traveled = 360 m
d) Average velocity = 72 kmph, Average acceleration = 0.72 m/s^2, Distance traveled = 100 m

Answer 1

The average velocity of the car is 7.2 km/s, the average acceleration is 7.2 m/s^2, and the distance traveled is 72 km.

The correct answer is option (b) Average velocity = 72 kmph, Average acceleration = 7.2 m/s^2, Distance traveled = 360 m

Step-by-step explanation:

To determine the average velocity of the car, we need to divide the total distance traveled by the time taken. In this case, the car traveled a distance of 72 km in 10 seconds, so the average velocity is 72 km/10 s = 7.2 km/s.

The average acceleration can be calculated by dividing the change in velocity by the time taken. In this case, the initial velocity was 0 km/h and the final velocity was 72 km/h, so the change in velocity is 72 km/h - 0 km/h = 72 km/h. Dividing this by the time taken (10 seconds), the average acceleration is 72 km/h / 10 s = 7.2 m/s^2.

To calculate the distance traveled, we can use the formula:

Distance = Average velocity * Time

Distance = 7.2 km/s * 10 s = 72 km

Thus, the correct answer is option (b) Average velocity = 72 kmph, Average acceleration = 7.2 m/s^2, Distance traveled = 360 m