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The present population of a village is 4375. If it increases at the rate of 8% per annum, what will be the population after 2 years? What was it 2 years ago?

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Final answer:

The population of a village currently standing at 4375 and growing at an 8% annual rate will reach approximately 5103 after two years. To find the population two years prior, you divide the current population by the growth factor squared, yielding approximately 3750.

Step-by-step explanation:

The present population of a village is 4375, and it increases at a rate of 8% per annum. To calculate the population after two years, we use the formula for exponential growth:

Future Population = Present Population × (1 + Growth Rate)^Number of Years

Therefore, after 2 years, the population would be:

4375 × (1 + 0.08)^2

4375 × 1.08^2

4375 × 1.1664

≈ 5103

The population would be approximately 5103.

To find out what the population was two years ago, we reverse the calculation:

Past Population = Present Population ÷ (1 + Growth Rate)^Number of Years

4375 ÷ 1.08^2

4375 ÷ 1.1664

≈ 3750

The population two years ago was approximately 3750.

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