Final answer:
To produce 150g of NH3,(B) 37g of H2 are needed.
Step-by-step explanation:
To determine the grams of H2 needed to react with 25g of N2 to produce 150g of NH3, we need to use the given balanced equation: N2(g) + 3H2(g) → 2NH3(g). From the equation, we can see that for every 3 moles of H2, 2 moles of NH3 are produced. To find the grams of H2 needed, we can set up a proportion using the molar masses of H2 and NH3. The molar mass of H2 is 2g/mol, and the molar mass of NH3 is 17g/mol. So, (3/2) * (gramsofH2/2) = (150gNH3/17gNH3). Solving for gramsofH2, we get gramsofH2 = (150gNH3 * 2gH2 * 2/17gNH3 * 3) = 35.3g.