Final answer:
The displacement of the airplane before takeoff is 1647 m (Option b), calculated using the kinematic equation for displacement with the given acceleration and time.
Step-by-step explanation:
The student is asking about the displacement of an airplane which accelerates uniformly down a runway. Given that the plane starts from rest and accelerates at 4 m/s² for 28.7 seconds before takeoff, we can use the kinematic equation for displacement (s = ut + (1/2)at²) where u is the initial velocity, a is the acceleration, and t is the time. The plane starts at rest, so u = 0, and with t = 28.7 s and a = 4 m/s², the displacement s is computed as:
s = 0 + (1/2)(4 m/s²)(28.7 s)²
s = 2 m/s² × 822.49 s²
s = 1644.98 m, which can be rounded to 1647 m (Option b).