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The vertices of ABC are A(-6, -7), B(-3, -1), and C(-5, 2). Find the vertices of A’B’C’, given the translation rules below.

a. (x, y) → (x – 2, y – 7) A’:____________ B’: ______________ C’ _________________
b. (x, y) → (x + 11, y +4) A’:____________ B’: ______________ C’ _________________
c. (x, y) → (x, y – 3) A’:____________ B’: ______________ C’ _________________

1 Answer

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Final answer:

To find the vertices of A’B’C’, apply the given translation rules to the coordinates of the original vertices.

Step-by-step explanation:

To find the vertices of A’B’C’ after applying the given translation rules, we need to apply each rule to the coordinates of the original vertices.

a. (x, y) → (x – 2, y – 7)

  • A’ = (-6 - 2, -7 - 7) = (-8, -14)
  • B’ = (-3 - 2, -1 - 7) = (-5, -8)
  • C’ = (-5 - 2, 2 - 7) = (-7, -5)

b. (x, y) → (x + 11, y + 4)

  • A’ = (-6 + 11, -7 + 4) = (5, -3)
  • B’ = (-3 + 11, -1 + 4) = (8, 3)
  • C’ = (-5 + 11, 2 + 4) = (6, 6)

c. (x, y) → (x, y – 3)

  • A’ = (-6, -7 - 3) = (-6, -10)
  • B’ = (-3, -1 - 3) = (-3, -4)
  • C’ = (-5, 2 - 3) = (-5, -1)
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